Question

1) -2*(x+6)+15=*(2x+4)+132) 2*(3x+2)-9=4*(2x-3)+7-2x​

Answer 1

Ответ:

1)-2(х+6)+15=(2х+4)+13

-2х-12+15=2х+4+13

-2х-2х=4+13+12-15

-4х=14

х= -3,5

2)2(3х+2)-9=4(2х-3)+7-2х

6х+4-9=8х-12+7-2х

6х-8х+2х=-12+7-4+9

-4х=0

х=0

Объяснение:

правильно?

Answer 2

To solve these two equations, you can start by simplifying and isolating the variable x in each equation. Here's how you can solve each equation step by step:

1. -2*(x+6)+15 = 2*(2x+4)+13

Step 1: Distribute the -2 and 2 on both sides of the equation:

-2x - 12 + 15 = 4x + 8 + 13

Step 2: Combine like terms on both sides:

-2x + 3 = 4x + 21

Step 3: Move all the x terms to one side of the equation and the constant terms to the other side:

-2x - 4x = 21 - 3

-6x = 18

Step 4: Divide both sides by -6 to solve for x:

x = 18 / -6

x = -3

So the solution for the first equation is x = -3.

2. 2*(3x+2) - 9 = 4*(2x-3) + 7 - 2x

Step 1: Distribute the 2 and 4 on both sides of the equation, and simplify:

6x + 4 - 9 = 8x - 12 + 7 - 2x

Step 2: Combine like terms on both sides:

6x - 5 = 6x - 5

Step 3: Notice that the variables cancel out, and you're left with a true statement. This means that the equation has infinitely many solutions, or the two sides are equal for all values of x.

So, the second equation has infinitely many solutions.