Question

Приведите одночлены к стандартному виду 7x³y• 3xy² = - 4m³n² • 2mn = ( - a⁴b³)• (-5a²b⁵) = 0,7xy•(-3xy) = 5m⁴n²• 6mn = срочно

Answer 1

1). 21x^4y^3; 2). -8m^4n^3; 3). 5a^6b^8; 4). -2,1x^2y^2; 5). 30m^5n^3. ^-это степень.

Answer 2

Simplifying Expressions

To simplify the given expressions and bring them to standard form, we can apply the rules of multiplication and exponentiation. Let's simplify each expression step by step:

1. 7x³y • 3xy²: To multiply these terms, we can multiply the coefficients (7 and 3) and add the exponents of the variables (x³ • x = x^(3+1) = x⁴, and y • y² = y^(1+2) = y³). Therefore, the simplified form is 21x⁴y³.

2. -4m³n² • 2mn: Multiplying the coefficients (-4 and 2) gives -8. For the variables, we add the exponents: m³ • m = m^(3+1) = m⁴, and n² • n = n^(2+1) = n³. Thus, the simplified form is -8m⁴n³.

3. (-a⁴b³) • (-5a²b⁵): When multiplying negative numbers, the product is positive. Multiplying the coefficients (1 and 5) gives 5. For the variables, we add the exponents: a⁴ • a² = a^(4+2) = a⁶, and b³ • b⁵ = b^(3+5) = b⁸. Therefore, the simplified form is 5a⁶b⁸.

4. 0.7xy • (-3xy): Multiplying the coefficients (0.7 and -3) gives -2.1. For the variables, we add the exponents: x • x = x^(1+1) = x², and y • y = y^(1+1) = y². Thus, the simplified form is -2.1x²y².

5. 5m⁴n² • 6mn: Multiplying the coefficients (5 and 6) gives 30. For the variables, we add the exponents: m⁴ • m = m^(4+1) = m⁵, and n² • n = n^(2+1) = n³. Therefore, the simplified form is 30m⁵n³.

To summarize, the expressions in standard form are: - 7x³y • 3xy² = 21x⁴y³ - -4m³n² • 2mn = -8m⁴n³ - (-a⁴b³) • (-5a²b⁵) = 5a⁶b⁸ - 0.7xy • (-3xy) = -2.1x²y² - 5m⁴n² • 6mn = 30m⁵n³

Please let me know if you need any further clarification or assistance!