Вопрос задан 24.10.2023 в 23:22. Предмет Алгебра. Спрашивает Алимова Алина.

ПОМОГИТЕ ПОЖАЛУЙСТА.Реши систему уравнений {10x−2y=2 −4x+4y=20

Смотреть ответ vereschakodasha vereschakodasha Ответ:(1.5;6.5) Обьяснение: {10x-2y=2|2           {20x-4y=4 -4x+4y=20             -4x+4y=20 16x=24                   15-2y=2 x=1.5                       -2y=-13                           Новые вопросы в Алгебра ДОПОМОЖІТЬ ДУЖЕ ПОТРІБНО!!!!!!!​ 3*a^2*b^3 - a*b^3 - a^3*a - a^2*b^2*b + (1/2)*a*b*2*b^2 + 4*a*b*(1/2)*a*b^2 Дробно рациональноое уравнение x/(x + 2) + (x + 2)/(x - 2) = 8/(x ^ 2 - 4) Сумма вклада в конце срока рассчитывается по формуле сложных процентов. Годовая процентная ставка составляет 0,5%, первоначальный депозит составил 800 … 0 евро.Рассчитайте стоимость вклада (евро) через три года. Решите биквадратное уравнение: б) x ^ 4 + 6x ^ 2 - 27 = 0 . 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Давайте решим каждую из ваших задач по очереди.

  1. Решение системы уравнений:

Система уравнений:

  1. 10x - 2y = 2
  2. -4x + 4y = 20

Для решения этой системы уравнений можно воспользоваться методом сложения или вычитания. Давайте используем метод сложения, чтобы избавиться от переменной y.

Умножим первое уравнение на 2 и второе уравнение на 5, чтобы сделать коэффициенты y в обоих уравнениях одинаковыми:

  1. 20x - 4y = 4
  2. -20x + 20y = 100

Теперь сложим оба уравнения:

(20x - 4y) + (-20x + 20y) = 4 + 100

Упростим:

16y = 104

Теперь найдем y:

y = 104 / 16 y = 6.5

Теперь, когда мы знаем y, мы можем найти x, используя любое из исходных уравнений. Давайте используем первое уравнение:

10x - 2(6.5) = 2

10x - 13 = 2

10x = 2 + 13 10x = 15

x = 15 / 10 x = 1.5

Итак, решение системы уравнений {10x - 2y = 2, -4x + 4y = 20} - это (x, y) = (1.5, 6.5).

  1. Ваш второй вопрос:

3a^2b^3 - ab^3 - a^3a - a^2b^2b + (1/2)ab2b^2 + 4ab*(1/2)ab^2

Давайте упростим это выражение:

3a^2b^3 - ab^3 - a^4 - a^2b^3 + ab^3 + 2a^2b^3 + 2a^2*b^3

Теперь сложим и упростим подобные члены:

3a^2b^3 - a^2b^3 - a^2b^3 + 2a^2b^3 = 2a^2b^3

Итак, упрощенное выражение равно 2a^2b^3.

  1. Ваш третий вопрос:

Для расчета стоимости вклада через три года с использованием формулы сложных процентов, мы можем использовать следующую формулу:

A=P(1+r/n)(nt)A = P(1 + r/n)^(nt)

Где:

  • A - конечная сумма (стоимость вклада через три года)
  • P - начальный депозит (800 евро)
  • r - годовая процентная ставка (0.5% или 0.005 в десятичной форме)
  • n - количество раз, когда проценты начисляются в год (предположим, что они начисляются ежегодно, поэтому n = 1)
  • t - количество лет (3 года)

Подставим значения в формулу:

A=800(1+0.005/1)(13)A = 800(1 + 0.005/1)^(1*3)

A=800(1.005)3A = 800(1.005)^3

A8001.015075125A ≈ 800 * 1.015075125

A812.06A ≈ 812.06

Итак, стоимость вклада через три года составит примерно 812.06 евро.

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