Question

(8x+2ay=1,(5x+4ay=2.​

Answer 1

8х+2аy=1

8х=1-2ау

х=1/8-1/4ау

Answer 2

To solve the system of equations:

1. 8x + 2ay = 1
2. 5x + 4ay = 2

You can use either the substitution method or the elimination method. I'll use the elimination method to solve this system of equations.

First, let's multiply both sides of the second equation by 2 to make the coefficients of 'ay' in both equations equal:

1. 8x + 2ay = 1
2. 10x + 8ay = 4

Now, you can subtract the first equation from the second equation to eliminate the 'ay' terms:

(10x + 8ay) - (8x + 2ay) = 4 - 1

This simplifies to:

2x + 6ay = 3

Now you have a system of two equations:

1. 8x + 2ay = 1
2. 2x + 6ay = 3

Next, you can solve for 'x' in terms of 'ay' from the first equation:

8x = 1 - 2ay x = (1 - 2ay)/8

Now, substitute this expression for 'x' into the second equation:

2((1 - 2ay)/8) + 6ay = 3

Simplify:

(1 - 2ay)/4 + 6ay = 3

Now, multiply both sides of the equation by 4 to eliminate the fraction:

1 - 2ay + 24ay = 12

Combine like terms:

1 + 22ay = 12

Subtract 1 from both sides:

22ay = 12 - 1

22ay = 11

Now, divide both sides by 22 to solve for 'ay':

ay = 11/22 ay = 1/2

Now that you've found the value of 'ay,' you can plug it back into either of the original equations to find the value of 'x.' Let's use the first equation:

8x + 2(1/2) = 1

8x + 1 = 1

Subtract 1 from both sides:

8x = 0

Now, divide by 8 to solve for 'x':

x = 0

So, the solution to the system of equations is x = 0 and ay = 1/2.