Question

Enpocmumu bupay: (x + 2) (X-5)- 3x (1-2x)​

Answer 1

Ответ:

Объяснение:

........

Answer 2

Відповідь:

Пояснення:

(x+2)(x-5)-3x(1-2x)=х²-5х+2х-10-3х+6х²=х²+7х²-5х+2х-3х-10=7х²-6х-10

Answer 3

To expand the given expression $(x + 2)(x - 5) - 3x(1 - 2x)$, you can use the distributive property to multiply the terms:

$(x + 2)(x - 5) - 3x(1 - 2x)$

Let's start by expanding each part of the expression:

1. Expand $(x + 2)(x - 5)$:

$(x + 2)(x - 5) = x(x) + x(-5) + 2(x) + 2(-5) = x^2 - 5x + 2x - 10$

Now, simplify the expression:

$x^2 - 3x - 10$

2. Expand $-3x(1 - 2x)$:

$-3x(1 - 2x) = -3x(1) - (-3x)(2x) = -3x + 6x^2$

Now, you have both parts expanded:

$x^2 - 3x - 10 - 3x + 6x^2$

Now, combine like terms by adding and subtracting the coefficients of the same-degree terms:

$x^2 + 6x^2 - 3x - 3x - 10$

Now, combine the like terms:

$7x^2 - 6x - 10$

So, the expanded expression is $7x^2 - 6x - 10$.