Question

X³-x²y-xy²+y³,при x=16,y=6

Answer 1

$x^3-x^2y-xy^2+y^3=x^2(x-y)-y^2(x-y)=(x-y)(x^2-y^2)=\\(x+y)(x-y)^2=22*10^2=2200$

Answer 2

To evaluate the expression $x^3 - x^2y - xy^2 + y^3$ when $x = 16$ and $y = 6$, we simply substitute these values into the expression:

$x^3 - x^2y - xy^2 + y^3 = (16)^3 - (16)^2(6) - 16(6)^2 + (6)^3$

Calculating this:

$4096 - 1536 - 576 + 216 = 320$