Question

6cos30°-2ctg45°-cos0

Answer 1

$6*\frac{\sqrt{3} }{2} -2*1-1=3\sqrt{2} - 1$

Answer 2

Let's calculate each term one by one:

1. $6\cos(30^\circ)$: The cosine of $30^\circ$ is $\frac{\sqrt{3}}{2}$, so $6\cos(30^\circ) = 6 \cdot \frac{\sqrt{3}}{2} = 3\sqrt{3}$.

2. $2\cot(45^\circ)$: The cotangent of $45^\circ$ is equal to 1. So, $2\cot(45^\circ) = 2 \cdot 1 = 2$.

3. $\cos(0^\circ)$: The cosine of $0^\circ$ is 1.

Now, let's add up these values:

$3\sqrt{3} + 2 - 1 = 3\sqrt{3} + 1$.

So, the final result is $3\sqrt{3} + 1$.