Question

12+3y-9=2x+10 8x+20=10+2(3x+2y)​

Answer 1

3у-2х=10-12+9

3у-2х=7

8х+20=10+6х+4у

2х-4у=-10

+

-2х+3у=7

——————

у=-3

-9-2х=7

-2х=16

2х=-16

х=-8

Ответ: (-8;-3)

Answer 2

To solve this system of linear equations, you can use the method of substitution or elimination. I'll use the elimination method in this example:

Given equations:

1. 12 + 3y - 9 = 2x + 10
2. 8x + 20 = 10 + 2(3x + 2y)

Let's simplify the equations first:

1. 3y + 3 = 2x + 10
2. 8x + 20 = 10 + 6x + 4y

Now, we can proceed to solve the system.

First, let's simplify equation 1 by subtracting 3 from both sides:

3y = 2x + 10 - 3 3y = 2x + 7

Now, let's simplify equation 2 by subtracting 6x and 10 from both sides:

8x + 20 - 10 - 6x = 4y

Simplify further:

2x + 10 = 4y

Now, we have two simplified equations:

3y = 2x + 7 2x + 10 = 4y

We can now use the elimination method to solve this system. Multiply the first equation by 2 and the second equation by 3 to make the coefficients of y in both equations equal:

2(3y) = 2(2x + 7) 3(2x + 10) = 3(4y)

This gives us:

6y = 4x + 14 6x + 30 = 12y

Now, we have two equations with equal coefficients for y:

6y = 4x + 14 6x + 30 = 12y

Since they both equal 6y, we can set them equal to each other:

4x + 14 = 6x + 30

Now, subtract 4x from both sides:

14 = 2x + 30

Subtract 30 from both sides:

-16 = 2x

Now, divide by 2:

x = -8

Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use equation 1:

3y = 2x + 7 3y = 2(-8) + 7 3y = -16 + 7 3y = -9

Now, divide by 3:

y = -3

So, the solution to the system of equations is:

x = -8 y = -3