Question

построить график функции y=-5x+3.Вычеслите координаты точки графика функции,абсцисса которой в два раза больше ординаты

Answer 1

СМ. ВЛОЖЕНИЕ

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Answer 2

Graph of the Function y = -5x + 3

To graph the function y = -5x + 3, we can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope (m) is -5 and the y-intercept (b) is 3.

Calculating the Coordinates of the Point on the Graph

We are asked to find the coordinates of a point on the graph where the abscissa (x-coordinate) is twice the ordinate (y-coordinate).

The equation for the given function is y = -5x + 3. To find the coordinates of the point where the abscissa is twice the ordinate, we can use the following steps:

1. Substitute y = -5x + 3 into the equation y = 2x to find the x-coordinate. 2. Substitute the x-coordinate into the original equation y = -5x + 3 to find the y-coordinate.

Let's calculate the coordinates of the point on the graph where the abscissa is twice the ordinate.

Calculation

1. Substitute y = -5x + 3 into the equation y = 2x: 2x = -5x + 3 7x = 3 x = 3/7

2. Substitute x = 3/7 into the original equation y = -5x + 3 to find the y-coordinate: y = -5(3/7) + 3 y = -15/7 + 21/7 y = 6/7

Result

The coordinates of the point on the graph where the abscissa is twice the ordinate are (3/7, 6/7).