Question

R) x2 +18x - 63=0.помогите решить пж​

Answer 1

Ответ:

Объяснение:

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Answer 2

х^2 + 18х - 63 = 0

D = b^2 - 4*a*c = 18^2 + 4*1*63 = 324 + 252 = 576, √D = 24

x1 = (-b-√D)/(2a) = (-18-24)/2 = -42/2 = -21

x2 = (-b+√D)/(2a) = (-18+24)/2 = 6/2 = 3

Ответ: -21; 3

Answer 3

Sure, I can help you solve this quadratic equation. To solve $x^2 + 18x - 63 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In your equation, $a = 1$, $b = 18$, and $c = -63$. Plug these values into the formula:

$x = \frac{-18 \pm \sqrt{18^2 - 4(1)(-63)}}{2(1)}$

Now, calculate the discriminant ($b^2 - 4ac$):

$18^2 - 4(1)(-63) = 324 + 252 = 576$

Now, substitute this back into the formula:

$x = \frac{-18 \pm \sqrt{576}}{2}$

Since $\sqrt{576} = 24$, you have:

$x = \frac{-18 \pm 24}{2}$

Now, consider both the positive and negative square root:

1. For the positive square root:

$x_1 = \frac{-18 + 24}{2} = \frac{6}{2} = 3$

2. For the negative square root:

$x_2 = \frac{-18 - 24}{2} = \frac{-42}{2} = -21$

So, the solutions to the equation $x^2 + 18x - 63 = 0$ are $x = 3$ and $x = -21$.