Question

0,2(7-2х)>2,3-0,3(х-6)

Answer 1

Ответ:

1,4-0,4x>2,3-0,3x+1,8

1,4-2,3-1,8>0,1x

-2,7>0,1x

-27>x

x<-27

Answer 2

To solve the inequality $0.2(7 - 2x) > 2.3 - 0.3(x - 6)$, you can follow these steps:

1. First, distribute the constants on both sides of the inequality:

   $1.4 - 0.4x > 2.3 - 0.3x + 1.8$

2. Combine like terms on both sides:

   $-0.4x + 1.4 > 4.1 - 0.3x$

3. Move the terms containing $x$ to one side of the inequality and the constants to the other side. You can do this by adding $0.4x$ to both sides and subtracting 1.4 from both sides:

   $-0.4x + 0.4x + 1.4 - 1.4 > 4.1 - 0.3x + 0.4x - 1.4$

   This simplifies to:

   $0 > 2.7 - 0.1x$

4. Now, subtract 2.7 from both sides to isolate the term with $x$ on the right side:

   $-2.7 > -0.1x$

5. Finally, divide both sides by -0.1. Since you're dividing by a negative number, the inequality sign will flip:

   $x < \frac{-2.7}{-0.1}$

   Simplify:

   $x < 27$

So, the solution to the inequality $0.2(7 - 2x) > 2.3 - 0.3(x - 6)$ is $x < 27$.