Question

Найдите при каком значении n верно равенство 2,3 В степени n+1 : 2,3 в степени 5n * 2,3 в степени 3n+5=1 Срочно! НЕ СПИСЫВАЕМ! ПИШИТЕ ПОДРОБНО, КАК ДЕЛАЛИ! ПОДРОБНО!!!!!!!!!!!!!!!! СПАСИБО ЗА ПОНИМАНИЕ !

Answer 1

Решение смотри в приложении

Answer 2

Для того чтобы решить ваш пример,
Нужно знать св-во степеней, а именно:

$x^a*x^b=x^{a+b} \\ x^a:x^b = x^{a-b} \\ (x^a)^b=x^{a*b}$

А также неплохо знать, что:
$a^0=1 ; 1^0=a^0$

Теперь решим наш пример:
$\frac{2,3^{n+1}}{2,3^{5n}}*2,3^{3n+5}=1 \\ 2,3^{n+1-5n+3n+5}=1 \\ 2,3^{6-n}=1 \\ 2,3^{6-n}=2,3^0 \\ 6-n=0 \\ n=6$ 

Ответ: $n=6$

Answer 3

Finding the Value of n in the Equation

To find the value of n in the equation 2.3^(n+1) = (2.3^(5n)) * (2.3^(3n+5)) = 1, we can start by simplifying the equation.

First, let's rewrite the equation using the exponentiation notation:

2.3^(n+1) = 2.3^(5n) * 2.3^(3n+5) = 1

Now, we can use the properties of exponents to simplify the equation further. According to the property of multiplying exponents with the same base, we can add the exponents:

2.3^(n+1) = 2.3^(8n+5) = 1

Since the bases are the same, we can equate the exponents:

n + 1 = 8n + 5

Now, let's solve for n:

Subtract n from both sides:

1 = 7n + 5

Subtract 5 from both sides:

-4 = 7n

Divide both sides by 7:

n = -4/7

Therefore, the value of n that satisfies the equation is n = -4/7.

Please note that the search results did not provide specific information about this equation. The solution was obtained through algebraic manipulation and solving for n.