Question

(2x+1/x)^2+(2x-1/x)-10=0

Answer 1

Ответ:

Объяснение:

Смотри фото

Answer 2

To solve the equation $(2x + 1/x)^2 + (2x - 1/x) - 10 = 0$, you can follow these steps:

1. Expand the expressions involving $x$ and $1/x$:

   $(4x^2 + 1 + 4x^2 - 1) + (2x - 1/x) - 10 = 0$

2. Combine like terms:

   $8x^2 + 2x - 1/x - 10 = 0$

3. Move the constant term to the other side of the equation:

   $8x^2 + 2x - 1/x = 10$

4. Multiply the entire equation by $x$ to eliminate the fraction:

   $8x^3 + 2x^2 - 1 = 10x$

5. Move all terms to one side to set the equation to zero:

   $8x^3 + 2x^2 - 10x - 1 = 0$

Now, you have a cubic equation. Unfortunately, there's no simple algebraic solution to cubic equations in general. You can use numerical methods or calculators to approximate the solutions, or you can use software like Python with numerical libraries to find the roots of the equation.