Question

(a/a-b+a/b)/a/a-b= (1/m-n-1/m+n)/2/3m-3m= (a+b/a-2b/a+b)*(a+b)=

Answer 1

Ответ:

м=0 воооооооооооооооооооооот

Answer 2

It looks like you have several expressions here, and I'll break down each one for you:

1. (a/a-b + a/b) / (a/a-b): To simplify this expression, you can find a common denominator, which is (a-b) for both fractions: = [(a/a-b) * (b/b)] / (a/a-b) Now, you can cancel out the common factor (a/a-b): = b

2. (1/m-n - 1/m+n) / (2/3m-3m): First, factor out the common factor of 1/m from both terms in the numerator: = (1/m * (1/n - 1/n)) / (2/3m-3m) Simplify the numerator: = (0) / (-5/3m) Since any number divided by 0 is undefined, this expression is undefined.

3. (a+b/a-2b) * (a+b): To simplify this expression, you can factor out the common factor of (a+b) in both terms: = (a+b) * (1/(a-2b)) So, the simplified expression is (a+b) * (1/(a-2b)).

If you have any further questions or need more clarification, please let me know.