Question

2) x2 + 5x + 6 = 0;​

Answer 1

Объяснение:

х2+5х+6=0

2х+5х+6=0

7х+6=0

7х=-6

х= -6/7

Answer 2

To solve the quadratic equation $x^2 + 5x + 6 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 1$, $b = 5$, and $c = 6$.

Now, plug these values into the quadratic formula:

$x = \frac{-5 \pm \sqrt{5^2 - 4(1)(6)}}{2(1)}$

Simplify:

$x = \frac{-5 \pm \sqrt{25 - 24}}{2}$

$x = \frac{-5 \pm \sqrt{1}}{2}$

Since the square root of 1 is 1, you have:

$x = \frac{-5 \pm 1}{2}$

Now, you can find two possible solutions:

1. When you add 1 to -5:

$x_1 = \frac{-5 + 1}{2} = \frac{-4}{2} = -2$

2. When you subtract 1 from -5:

$x_2 = \frac{-5 - 1}{2} = \frac{-6}{2} = -3$

So, the solutions to the quadratic equation $x^2 + 5x + 6 = 0$ are $x = -2$ and $x = -3$.