Question

Cos²x-sin²x=0?????????

Answer 1

cos²x-sin²x=0

по формуле двойного угла cos²x-sin²x=cos2x

cos2x=0

2x=π/2 + πn  n∈Z

x=π/4+ πn/2

Answer 2

Ответ:
x=π/4+πn/2
Объяснение:
cos²x-sin²x=cos2x
cos2x=0
2x=π/2+πn
x=π/4+(πn)/2

Answer 3

The equation you've written, cos²x - sin²x = 0, is actually a trigonometric identity known as the Pythagorean Identity. It relates the square of the cosine of an angle (cos²x) and the square of the sine of the same angle (sin²x) to 1. In other words, this identity is always true for any real value of x.

Mathematically, it can be expressed as:

cos²x - sin²x = 1

So, the equation you've provided, cos²x - sin²x = 0, is not accurate. The correct equation is cos²x - sin²x = 1.