Question

A) 9x2 - 12x + 4; 6б) 0,5x2 - 2x + 4;​

Answer 1

Ответ:

$1)9 {x}^{2} - 12x + 4 = 0 \\ d = 144 - 4 \times 4 \times 9 = 144 - 144 = 0 \\ x = \frac{12}{18} = \frac{2}{3}$

$2)0.5 {x}^{2} - 2x + 4 = 0 \\ d = 4 - 4 \times 4 \times 0.5 = 4 - 8 = - 4$

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уравнение не имеет корней

Answer 2

It seems like you have two quadratic expressions, and you might want to perform some operations on them. Let's go through each one:

A) 9x^2 - 12x + 4: This is a quadratic expression, and it can be factored as follows:

9x^2 - 12x + 4 = (3x - 2)(3x - 2)

So, the factorization of the expression is (3x - 2)^2.

B) 0.5x^2 - 2x + 4: This is also a quadratic expression. Let's first multiply the entire expression by 2 to get rid of the decimal:

2(0.5x^2 - 2x + 4) = x^2 - 4x + 8

Now, we can try to factor it:

x^2 - 4x + 8 does not have simple integer factors, so it remains in factored form as x^2 - 4x + 8.

If you have any specific operations or questions about these expressions, please let me know, and I'll be happy to assist further.