Question

( x+2y=3 (x2(не 2 а квадрат) +3ху - у2(тоже квадрат) =3

Answer 1

Ответ и решение на фото

если у тебя есть возможность, сделай мой ответ лучшим. сверху, над ответом, есть голубая функция «сделать лучшим ответом» с коронкой

Answer 2

It seems like you have a system of equations with two variables, x and y:

1. $x + 2y = 3$
2. $x^2 + 3xy - y^2 = 3$

You can solve this system of equations by using various methods, such as substitution, elimination, or matrix algebra. Here's one way to solve it using the substitution method:

From equation (1), you can express $x$ in terms of $y$: $x = 3 - 2y$

Now, substitute this expression for $x$ into equation (2):

$(3 - 2y)^2 + 3(3 - 2y)y - y^2 = 3$

Now, expand and simplify this equation:

$9 - 12y + 4y^2 + 9y - 6y^2 - y^2 = 3$

Combine like terms:

$4y^2 - 4y - 3 = 0$

Now, this is a quadratic equation in $y$. You can solve it using the quadratic formula:

$y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 4$, $b = -4$, and $c = -3$. Plug these values into the formula:

$y = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(4)(-3)}}{2(4)}$

Simplify:

$y = \frac{4 \pm \sqrt{16 + 48}}{8}$

$y = \frac{4 \pm \sqrt{64}}{8}$

$y = \frac{4 \pm 8}{8}$

Now, you have two possible solutions for $y$:

1. $y_1 = \frac{12}{8} = \frac{3}{2}$
2. $y_2 = \frac{-4}{8} = -\frac{1}{2}$

Now that you have found the values of $y$, you can plug them back into equation (1) to find the corresponding values of $x$:

For $y = \frac{3}{2}$: $x = 3 - 2\left(\frac{3}{2}\right) = 3 - 3 = 0$

For $y = -\frac{1}{2}$: $x = 3 - 2\left(-\frac{1}{2}\right) = 3 + 1 = 4$

So, the solutions to the system of equations are:

1. $x = 0$ and $y = \frac{3}{2}$
2. $x = 4$ and $y = -\frac{1}{2}$