Question

X²-25 ------- =0 x-5

Answer 1

Ответ:

На фотке,

Объяснение:

Хорошего дня, успехов в учёбе,

Answer 2

To solve the equation (x^2 - 25) / (x - 5) = 0, you can start by factoring the numerator and denominator:

(x^2 - 25) = (x + 5)(x - 5)

Now, your equation becomes:

(x + 5)(x - 5) / (x - 5) = 0

Since (x - 5) is in the denominator, we need to be careful about this. We cannot simply cancel it out because it would make the equation undefined when x = 5. Instead, we need to consider that if the denominator is 0, the fraction is undefined, so the only way for the entire fraction to equal 0 is if the numerator is 0.

So, you can set the numerator (x + 5)(x - 5) equal to 0:

(x + 5)(x - 5) = 0

Now, you can solve for x by setting each factor equal to 0:

x + 5 = 0 --> x = -5 x - 5 = 0 --> x = 5

So, there are two solutions to the equation:

x = -5 x = 5

However, remember that the original equation was (x^2 - 25) / (x - 5) = 0. When x = 5, the denominator becomes 0, which makes the fraction undefined. So, the only valid solution is:

x = -5