Question

1) x ^ 2 + 0, 8x = 0​

Answer 1

Ответ:

х²+0,8x=0

х²+4/5x=0

5х²+4x=0

x*(5x+4)=0

x=0

5x+4=o

x=0

x= -4/5

x1= -4/5, x2=0

Answer 2

Ответ:

x(x+0,8)=0

x=0

x+0,8=0

x=-0,8

Объяснение:

Answer 3

It seems like you have an equation that you want to solve for the variable x:

x^2 + 0.8x = 0

To solve this quadratic equation, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 1, b = 0.8, and c = 0. So, plug these values into the formula:

x = (-0.8 ± √(0.8² - 4(1)(0))) / (2(1))

x = (-0.8 ± √(0.64)) / 2

x = (-0.8 ± 0.8) / 2

Now, you have two possible solutions:

1. x = (-0.8 + 0.8) / 2 = 0 / 2 = 0
2. x = (-0.8 - 0.8) / 2 = -1.6 / 2 = -0.8

So, the solutions to the equation x^2 + 0.8x = 0 are x = 0 and x = -0.8.