Question

1√2-√2,4π÷22√2,4•10π-1

Answer 1

Ответ:

1√2-√2,4π÷22√2,4•10π-1 = (1√2) - (√24π) / (22√24) * (10π) - 1 = √2 - 4π/44 * 10π - 1 = √2 - 10π - 1 = -9 - 10π

Answer 2

It looks like you've provided a series of mathematical expressions. Let's break them down one by one:

1. √2 - √2: This expression simplifies to 0 because the square root of 2 minus the square root of 2 equals zero.

2. 4π ÷ 2√2: To simplify this expression, you can first divide 4π by 2, which gives you 2π. Then, you can divide 2π by 2√2. To simplify further, you can rationalize the denominator by multiplying both the numerator and denominator by √2:

   (2π * √2) / (2√2 * √2) = (2π * √2) / (2 * 2) = π√2/2

3. 4 • 10π - 1: This expression is straightforward to calculate:

   4 • 10π - 1 = 40π - 1

So, the simplified versions of the expressions are as follows:

1. √2 - √2 = 0
2. 4π ÷ 2√2 = π√2/2
3. 4 • 10π - 1 = 40π - 1