Question

4(5x−10)2−20(5x−10)+16=0

Answer 1

20X-40*2-100X-200+16=0
-80X-264=0
80X=-264
X=3.3

Answer 2

20X-40*2-100X-200+16=0
-80X-264=0
80X=-264
X=3.3

Answer 3

To solve the quadratic equation 4(5x - 10)^2 - 20(5x - 10) + 16 = 0, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, you have: a = 4 b = -20 c = 16

Now, plug these values into the quadratic formula:

$x = \frac{-(-20) \pm \sqrt{(-20)^2 - 4(4)(16)}}{2(4)}$

Simplify the equation:

$x = \frac{20 \pm \sqrt{400 - 256}}{8}$

$x = \frac{20 \pm \sqrt{144}}{8}$

Now, take the square root of 144:

$x = \frac{20 \pm 12}{8}$

Now, you have two possible solutions:

1. When you add 12 to 20: $x_1 = \frac{20 + 12}{8} = \frac{32}{8} = 4$

2. When you subtract 12 from 20: $x_2 = \frac{20 - 12}{8} = \frac{8}{8} = 1$

So, the solutions to the equation are: $x_1 = 4$ $x_2 = 1$