Question

(X-7)•(2+x)=3 ..……………

Answer 1

2x+x²-14-7x =3
-5x+x²-14=3
-5x+x²-14=3
x²-5x-17=3
5x⁴+3+17
x⁴=20
x⁴=4

Answer 2

Let's solve the equation step by step:

Given equation: (X - 7) * (2 + x) = 3

First, distribute the terms: 2x + x^2 - 14 - 7x = 3

Combine like terms: x^2 - 5x - 14 = 3

Move the constant term to the other side of the equation: x^2 - 5x - 14 - 3 = 0

Simplify: x^2 - 5x - 17 = 0

Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where: a = 1 b = -5 c = -17

We can solve this quadratic equation using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Substitute the values: x = (5 ± √((-5)^2 - 4 * 1 * -17)) / (2 * 1) x = (5 ± √(25 + 68)) / 2 x = (5 ± √93) / 2

So, the solutions are: x = (5 + √93) / 2 x = (5 - √93) / 2

These are the two possible values for x that satisfy the given equation.

Answer 3

Let's solve the equation step by step:

Given equation: (X-7) * (2+x) = 3

First, distribute the terms on the left side of the equation: 2x + x^2 - 7x - 7 = 3

Combine like terms: x^2 - 5x - 7 = 3

Now, move the constant term to the right side of the equation: x^2 - 5x - 7 - 3 = 0

Simplify the right side: x^2 - 5x - 10 = 0

This is a quadratic equation. To solve for x, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = 1, b = -5, and c = -10. Plugging these values in: x = (5 ± √((-5)^2 - 4 * 1 * -10)) / (2 * 1) x = (5 ± √(25 + 40)) / 2 x = (5 ± √65) / 2

So, the solutions for x are: x = (5 + √65) / 2 x = (5 - √65) / 2

These are the two possible solutions for the given equation.