Question

-7х^2-4х+11=0 надо решать с дискриминантом

Answer 1

-7x^2 - 4x + 11 =0
D=b^2-4ac, D=(-4)^2 + 4*7*11 = 16+308=324
x1=-b-кореньD/2a x1=4-18/-14 = 1
x2=-b+кореньD/2a x2=4+18/-14 = - 1 4/7

Answer 2

Выделим здесь все коэффициенты перед членами;
а=-7; b=-4; с=11.
Находим дискриминант:
D=b^2-4*a*c=16-4*(-7)*11=16+308=324
Находим корни квадратного уравнения:
х1,2=(-b±√D)/2a= 4±18 / 2*(-7)= -1 целая 4 седьмых; 1.
Ответ: х1=-1 целая 4 седьмых; х2=1.

Answer 3

To solve the quadratic equation -7x^2 - 4x + 11 = 0 using the discriminant, we first need to find the discriminant and then apply the quadratic formula. The quadratic formula is:

x = (-b ± √(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

In this case, a = -7, b = -4, and c = 11. Now let's calculate the discriminant (Δ):

Δ = b^2 - 4ac Δ = (-4)^2 - 4 * (-7) * 11 Δ = 16 + 308 Δ = 324

Now, we have the discriminant (Δ) which is 324. Depending on the value of the discriminant, we can determine the nature of the roots:

1. If Δ > 0, the equation has two distinct real roots.
2. If Δ = 0, the equation has one real root (a repeated root).
3. If Δ < 0, the equation has two complex roots (conjugate pair).

Since Δ is positive (Δ > 0), the equation -7x^2 - 4x + 11 = 0 has two distinct real roots.

Now, we can use the quadratic formula to find the values of x:

x = (-(-4) ± √(324)) / (2 * (-7)) x = (4 ± 18) / (-14)

Now, we have two possible values for x:

1. x = (4 + 18) / (-14) = 22 / (-14) = -11/7 ≈ -1.57
2. x = (4 - 18) / (-14) = -14 / (-14) = 1

So, the solutions to the equation are approximately x ≈ -1.57 and x = 1.