Question

-9x в квадрате +1 больше или меньше 0

Answer 1

Больше, потому что в квадрате.
Значит всегда положительный

Answer 2

To determine whether the expression -9x^2 + 1 is greater than or less than 0, we need to find the value of x that makes the expression either positive or negative.

Let's solve for x:

-9x^2 + 1 > 0

To make the expression greater than 0, the quadratic expression -9x^2 must be less than 1. Divide both sides by -9 (note that dividing by a negative number changes the inequality direction):

x^2 < 1/(-9)

x^2 < -1/9

However, there's an issue with this inequality. There's no real number value for x that would satisfy this inequality because the square of any real number is always greater than or equal to 0. Thus, there is no real solution to make the expression -9x^2 + 1 greater than 0.

On the other hand, to find when the expression is less than 0, we have:

-9x^2 + 1 < 0

To make the expression less than 0, the quadratic expression -9x^2 must be greater than 1. Again, divide both sides by -9:

x^2 > 1/(-9)

x^2 > -1/9

Since the square of any real number is greater than or equal to 0, there are infinite real values of x that satisfy this inequality. Thus, the expression -9x^2 + 1 is less than 0 for any real value of x.

In summary, the expression -9x^2 + 1 is less than 0 for all real values of x.