Question

A^2 - 12 a-4 a ______ - ___ + ___ _ a^2+4a a a+4 Спростіть вираз

Answer 1

$\frac{a^2-12}{a^2+4a} -\frac{a-4}{a} +\frac{a}{a+4} =\frac{a^2-12-(a+4)*(a-4)+a*a} {a(a+4)} =\frac{a^2-12-(a^2-16)+a^2}{a(a+4)} =\frac{a^2+4}{a^2+4a}$

Answer 2

To simplify the given expression, let's combine like terms and perform the necessary calculations step by step:

1. Combine like terms: A^2 - 12a - 4a^3 + a^2 + 4a - a^3 - 4

2. Group similar terms: (A^2 + a^2) + (-4a^3 - a^3) + (-12a + 4a) - 4

3. Combine the grouped terms: A^2 + a^2 - 5a^3 - 8

So, the simplified expression is: A^2 + a^2 - 5a^3 - 8