Question

Hep me pleascos a/sin a + (sina-ctga)

Answer 1

$\frac{cosa}{sina} + (sina - ctga) = ctga + sina - ctga = sina$



ОТВЕТ: sina

Answer 2

sin a .........................................................

Answer 3

It seems like you want help simplifying the expression:

a/sin(a) + (sin(a) - cot(a))

To simplify this expression, we'll start by expressing cot(a) in terms of sin(a) and cos(a) since cot(a) is the reciprocal of tan(a).

Recall that cot(a) = cos(a) / sin(a).

Now, substitute cot(a) with its equivalent expression:

a/sin(a) + (sin(a) - cos(a)/sin(a))

Now, let's find a common denominator for the two fractions:

The common denominator is sin(a).

So the expression becomes:

(a + sin^2(a) - cos(a)) / sin(a)

Now, the numerator can be simplified by combining like terms:

(a - cos(a)) / sin(a)

And that's the simplified expression.

Please note that this is not an identity or equation that can be further simplified or solved. It's just a simplified expression of the given input.