
-х^2+6х-70>срочнооооо


Ответы на вопрос

а=-1, b=6, c=-70
D=b^2-4ac
D=6^2-4*(-1)*(-70)=36-4*70=36-280=-244<0=> корней нет



To solve the inequality -x^2 + 6x - 70 > 0, we'll follow these steps:
Step 1: Set the inequality to zero to find critical points: -x^2 + 6x - 70 = 0
Step 2: Find the critical points (where the inequality might change): To find the roots of the quadratic equation -x^2 + 6x - 70 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
where a = -1, b = 6, and c = -70
x = (-(6) ± √((6)^2 - 4(-1)(-70))) / 2(-1) x = (-6 ± √(36 - 280)) / -2 x = (-6 ± √(-244)) / -2 x = (-6 ± 2i√61) / -2
The roots are complex numbers because the discriminant (b^2 - 4ac) is negative.
Step 3: Analyze the inequality using critical points: Since the coefficient of x^2 is negative (-1), the parabola opens downward. The inequality -x^2 + 6x - 70 > 0 means that the quadratic expression is positive between the two complex roots.
Step 4: Final Answer: The solution to the inequality -x^2 + 6x - 70 > 0 is all x values between the two complex roots, which are (-6 + 2i√61) / -2 and (-6 - 2i√61) / -2.
Since these roots are complex numbers and cannot be compared directly on the real number line, the inequality doesn't have a simple real number solution. If you need further assistance or if the inequality was meant to be different, please let me know!


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