Question

Найди sint и cost, если t может принимать значения −π?

Answer 1

Если я правильно понял,что t=$\pi$,то

sin(-п)=1

cos(-п)=0

Answer 2

To find the values of sin(t) and cos(t) when t can take the value of -π, we can simply plug in the value of t into the trigonometric functions.

First, let's recall the definitions of sine and cosine:

• sine (sin): sin(t) = opposite/hypotenuse
• cosine (cos): cos(t) = adjacent/hypotenuse

In a unit circle, which has a radius of 1, the hypotenuse is always 1.

For t = -π, we can visualize it as a point on the unit circle located at an angle of -π radians (180 degrees) from the positive x-axis, in the third quadrant.

The coordinates of a point on the unit circle in the third quadrant are (-cos(t), -sin(t)).

So, for t = -π:

sin(-π) = -sin(π) = -0 = 0 cos(-π) = -cos(π) = -(-1) = 1

Therefore, when t can take the value of -π:

sin(t) = 0 cos(t) = 1