Question

Sinx×(-cosx)×(-tgx)/-cosx×(-tgx)×(-sinx) правильный ответ

Answer 1

-1

sin(x)*cos(x)*tg(x)=sin^2(x);

-cos(x)*tg(x)*sin(x)=sin^2(x);

sin^2(x)/-sin^2(x)=-1

Answer 2

To simplify the given expression, we can cancel out common factors in the numerator and denominator. Let's break it down step by step:

1. sin(x) * (-cos(x)) * (-tan(x)) = sin(x) * cos(x) * tan(x) [(-1) * (-1) = 1]

2. -cos(x) * (-tan(x)) = cos(x) * tan(x) [(-1) * (-1) = 1]

3. -sin(x) = -sin(x)

Now, putting it all together:

(sin(x) * cos(x) * tan(x)) / (cos(x) * tan(x) * (-sin(x)))

We can see that both the numerator and the denominator have the factor cos(x) * tan(x), so they cancel out:

= 1 / (-sin(x))

So, the final simplified expression is:

-1 / sin(x) or simply -csc(x) (where csc(x) represents the cosecant of x).