Question

(3^4)^3 * 3^5:3^2=27^2

Answer 1

Ответ: Ложь
Решение:
$(3 {}^{4} )3 {}^{3} \times 3 {}^{5} \div 3 {}^{2} = 27 {}^{2} \\ 3 {}^{12} \times 3 {}^{5} \div 3 {}^{2} = 729 \\ 3 {}^{15} = 3 {}^{6} \\ 15 = 6$

Answer 2

Let's solve the expression step by step:

1. (3^4)^3: First, we evaluate the exponent inside the parentheses. (3^4)^3 = 3^(4*3) = 3^12

2. 3^5:3^2: Next, we perform the division of exponents. 3^5:3^2 = 3^(5-2) = 3^3

3. Now, the original expression becomes: 3^12 * 3^3

4. To simplify this, we apply the rule that says when multiplying with the same base, you add the exponents: 3^12 * 3^3 = 3^(12+3) = 3^15

So, the final simplified expression is 3^15.

Now, let's check if the statement "27^2 = 3^15" is true:

27^2 = 27 * 27 = 729

And 3^15 = 14348907

Since 729 is not equal to 14348907, the statement "27^2 = 3^15" is not true.