Question

(1-3y)³Алгебра 7 класс задание 33.2

Answer 1

Ответ:

Объяснение: Воспользуемся формулой:

(a-b)³=a³-3a²b+3ab²-b³

(1-3y)³=1-(3*1²*3y)+3*1*(3y)²-(3y)³=1-9y+9y²-9y³

Answer 2

I apologize, but I don't have access to specific textbooks or their contents beyond my knowledge cutoff date in September 2021. Therefore, I don't have the exact content of the "Algebra 7th grade, task 33.2" you mentioned. However, I can provide some general guidance on solving problems related to algebraic expressions for 7th-grade level.

If you have an algebraic expression like (1-3y)³, it means you need to raise the entire expression to the power of 3. To do this, you can use the binomial expansion formula for (a - b)³:

(a - b)³ = a³ - 3a²b + 3ab² - b³

In this case, a = 1 and b = 3y. Substituting the values:

(1 - 3y)³ = 1³ - 3 * 1² * (3y) + 3 * 1 * (3y)² - (3y)³ = 1 - 3 * 1 * 3y + 3 * 9y² - 27y³ = 1 - 9y + 27y² - 27y³

So the simplified form of the expression (1 - 3y)³ is 1 - 9y + 27y² - 27y³.

If this is not what you were looking for, please provide more context or information about the specific task, and I'll be happy to assist further.