Question

Хелп please 14c+49c^2+1=0

Answer 1

Это квадратное уравнение
Сначала переставим элементы,так будет удобнее
49с^2+14с+1=0

a=49
b=14
c=1

D=b^2-4•a•c= 196-196=0
При нуле формула х=-b/2a=-14/2•49=-14/98=-1/7

Ответ:-1/7

Отметь как лучший пожалуйста

Answer 2

Of course, I'd be happy to help you with the equation! It looks like you have a quadratic equation, which is a second-degree polynomial equation in the form of ax^2 + bx + c = 0.

Your equation is: 14c + 49c^2 + 1 = 0

To solve this equation, we need to find the value(s) of "c" that satisfy the equation.

Unfortunately, this equation is not easily solvable by factoring, so we will use the quadratic formula:

For a quadratic equation of the form ax^2 + bx + c = 0, the quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In your case, a = 49, b = 14, and c = 1. Plug these values into the formula:

c = (-(14) ± √((14)^2 - 4 * 49 * 1)) / 2 * 49

Now, let's solve the equation:

c = (-14 ± √(196 - 196)) / 98 c = (-14 ± √0) / 98

Since the discriminant (b^2 - 4ac) is zero, we only get one solution:

c = (-14 + 0) / 98 c = -14 / 98 c = -1/7

So, the solution to the equation is c = -1/7.