Question

2(x^2+1)−4x=0. срочно

Answer 1

2x^2 +2 - 4x = 0

кв уравнение

D= b^2 - 4ac = 4+32=36

x1,2 = (-b +-кореньd)/2a

x1= 1

x2=-2

Answer 2

2x2+2-4x=0 / :2
x2-2x+1=0
D=4-4*1*1=0
x=-b/2a
x1=-2/2=-1

Answer 3

To solve the equation 2(x^2 + 1) - 4x = 0, we need to find the values of x that satisfy the equation. Let's go step by step:

Step 1: Expand the equation: 2x^2 + 2 - 4x = 0

Step 2: Rearrange the equation to set it to zero: 2x^2 - 4x + 2 = 0

Step 3: To solve this quadratic equation, we can use the quadratic formula: The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

where a = 2, b = -4, and c = 2.

Step 4: Plug in the values into the quadratic formula: x = [-( -4) ± √((-4)^2 - 4 * 2 * 2)] / (2 * 2) x = (4 ± √(16 - 16)) / 4 x = (4 ± √0) / 4

Step 5: Simplify further: Since the square root of 0 is 0, we have two identical solutions: x = (4 + 0) / 4 = 4 / 4 = 1 x = (4 - 0) / 4 = 4 / 4 = 1

So, the equation has a single solution: x = 1.