Question

X^2+4x=5 через диксременант​

Answer 1

x^2+4x-5=0

D=b^2-4ac=16-4*1*(-5)=16+20=(36)=6

x1= -4-6/2 = -5

x2= -4+6/2=1

ответ -5;1

Answer 2

x^2+4x=5

x^2+4x-5=0

D=4^2-4(-5)=16+20=36

x1= -4-6/2=-10/2=-5

x2= -4+6= 2/2=1

Ответ: х1= -5;

х^2= 1

Answer 3

To find the solutions of the quadratic equation $x^2 + 4x = 5$ using the discriminant, we first need to rewrite the equation in standard form: $ax^2 + bx + c = 0$.

Our given equation is $x^2 + 4x - 5 = 0$, so $a = 1$, $b = 4$, and $c = -5$.

The discriminant, denoted by $\Delta$, is given by the formula:

$\Delta = b^2 - 4ac$

Now, let's plug in the values of $a$, $b$, and $c$:

$\Delta = (4)^2 - 4(1)(-5)$ $\Delta = 16 + 20$ $\Delta = 36$

The discriminant is $36$.

Now, the solutions of the quadratic equation are found using the quadratic formula:

$x = \frac{-b \pm \sqrt{\Delta}}{2a}$

Plugging in the values of $\Delta$, $a$, and $b$:

$x = \frac{-4 \pm \sqrt{36}}{2(1)}$

$x = \frac{-4 \pm 6}{2}$

Now, we have two cases:

1. $x = \frac{-4 + 6}{2} = \frac{2}{2} = 1$
2. $x = \frac{-4 - 6}{2} = \frac{-10}{2} = -5$

Therefore, the solutions to the equation $x^2 + 4x = 5$ are $x = 1$ and $x = -5$.