Question

Дано: b1 = 16; q = 1/2 Найти: b7

Answer 1

b(1) = 16

q = 1/2

b(7) - ?

b(n) = b(1) * q^{n-1}

b(7) = b(1) * q^{6}

b(7) = 16 * (1/2)^{6) = 16 * 1/64 = 1/4

Answer 2

To find the value of b7 in the given geometric sequence, where b1 = 16 and the common ratio (q) is 1/2, we can use the formula for the nth term of a geometric sequence:

b_n = b1 * q^(n-1)

where b_n is the nth term, b1 is the first term, q is the common ratio, and n is the term number we want to find (in this case, n = 7).

Now, let's substitute the given values:

b7 = 16 * (1/2)^(7-1) = 16 * (1/2)^6 = 16 * (1/64) = 1/4

Therefore, the value of b7 is 1/4.