Question

(4-y)в квадрате - y(y+1) при y= минус одна десятая​

Answer 1

$(4 - y) {}^{2} - y(y + 1) \\ = 16 - 8y + {y}^{2} - {y}^{2} - y - 9y + 16 - 9 \times 0.1 + 16 = - 0.9 + 16 = 15.1$

Answer 2

To find the value of the expression (4-y)^2 - y(y+1) when y = -1/10, we can substitute y with -1/10 and perform the calculations:

Let's first substitute y = -1/10 into the expression:

(4 - (-1/10))^2 - (-1/10)(-1/10 + 1)

Now, let's simplify the expression step by step:

(4 + 1/10)^2 - (-1/10)(-1/10 + 1)

Next, we calculate the squared term:

(41/10)^2 - (-1/10)(-1/10 + 1)

Now, we simplify further:

(41/10 * 41/10) - (-1/10)(-9/10)

Now, we multiply the fractions:

(1681/100) - (9/100)

Next, we find a common denominator and subtract the fractions:

(1681 - 9)/100

Finally, we perform the subtraction:

1672/100

Now, let's simplify the fraction:

1672 ÷ 100 = 16.72

So, the value of the expression (4-y)^2 - y(y+1) when y = -1/10 is 16.72.