Question

5a(2-a)+6a(a-7)= 20x+5(x-2)²= 25y-y³= -4x²+8xy-4y²= 16 в² - - = 81 -y²+2y-5= (3x+x²)²-x²(x-5) (x+5)+2x(8-3x²)=

Answer 1

Решеение во вложениии

Answer 2

Let's solve each of these equations step by step:

1. 5a(2-a) + 6a(a-7) = ?

To simplify the expression, we'll first distribute the terms: 5a(2-a) = 10a - 5a² 6a(a-7) = 6a² - 42a

Now, combine the terms: 10a - 5a² + 6a² - 42a

Next, combine the like terms: 10a + (6a² - 5a²) - 42a 10a + a² - 42a

Finally, combine like terms again: (10a - 42a) + a² -32a + a²

So the simplified expression is: a² - 32a

2. 20x + 5(x-2)² = ?

First, simplify the square term, (x-2)²: (x-2)² = (x-2)(x-2) = x² - 2x - 2x + 4 = x² - 4x + 4

Now, substitute this into the original equation: 20x + 5(x² - 4x + 4) = 20x + 5x² - 20x + 20

Combine the like terms: 20x - 20x + 5x² + 20

Simplify further: 5x² + 20

3. 25y - y³ = ?

This equation is already in a simplified form.

4. -4x² + 8xy - 4y² = ?

This equation is already simplified as well.

5. 16v² - ? = 81 - y² + 2y - 5

The given equation has a missing term on the left-hand side. We can't solve it without knowing what should be on the left-hand side.

6. (3x + x²)² - x²(x-5)(x+5) + 2x(8-3x²) = ?

First, square the binomial (3x + x²): (3x + x²)² = (3x + x²)(3x + x²) = 9x² + 3x³ + 3x² + x⁴ = x⁴ + 3x³ + 12x²

Next, expand the second term, x²(x-5)(x+5): x²(x-5)(x+5) = x²(x² + 5x - 5x - 25) = x²(x² - 25) = x⁴ - 25x²

Now, expand the third term, 2x(8-3x²): 2x(8-3x²) = 16x - 6x³

Now, substitute all the expanded terms into the original equation: x⁴ + 3x³ + 12x² - (x⁴ - 25x²) + 16x - 6x³

Combine like terms: x⁴ + 3x³ + 12x² - x⁴ + 25x² + 16x - 6x³

Simplify further: (3x³ - 6x³) + (x⁴ - x⁴) + (12x² + 25x²) + 16x -3x³ + 37x² + 16x

So the simplified expression is: -3x³ + 37x² + 16x

If there are any other specific equations you'd like to solve or if you need further clarification, feel free to ask!