Question

22(х-1)/х =21х-9 /х+1​

Answer 1

Ответ:

х1 = 2;

х2 = -11

Объяснение:

Переносим все в левую часть

22(х - 1)/х -(21х - 9/х + 1) = 0

Приводим к общему знаменателю (домножаем первую дробь на знаменатель второй, а вторую на знаменатель первой)

22(х - 1)(х + 1) - (21х - 9)х=0

22(х*в квадрате* - 1)(-21х + 9)х=0

22х*в квадрате* - 22 - 21х*в квадрате* + 9х=0

Сокращаем

1х*в квадрате* + 9х - 22=0

Д=9*в квадрате* -4×1×(-22) = 81 + 88 = 169

х1 = (-9 + √169)/2 = 2

х2 =(-9 - √169)/2 = -11

Одз:

х(х + 1) = 0

х≠0

х≠-1

Answer 2

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Answer 3

To solve the equation, we need to find the value(s) of 'x' that satisfy the equation:

$\frac{22(x-1)}{x} = \frac{21x-9}{x+1}$

To do this, let's start by cross-multiplying to eliminate the denominators:

$22(x-1)(x+1) = (21x-9)(x)$

Next, we'll expand both sides of the equation:

$22(x^2 + x - x - 1) = 21x^2 - 9x$

Now, simplify:

$22(x^2 - 1) = 21x^2 - 9x$

Expand further:

$22x^2 - 22 = 21x^2 - 9x$

Now, move all the terms to one side of the equation:

$22x^2 - 21x^2 + 9x - 22 = 0$

Combine like terms:

$x^2 + 9x - 22 = 0$

Now we have a quadratic equation. To solve for 'x,' we can use factoring, completing the square, or the quadratic formula. In this case, we'll use factoring:

$(x + 11)(x - 2) = 0$

Now, set each factor to zero and solve for 'x':

1. $x + 11 = 0$
   $x = -11$

2. $x - 2 = 0$
   $x = 2$

So, the values of 'x' that satisfy the original equation are $x = -11$ and $x = 2$.