Question

Z1=-6+2i;z2=4-6i найти: z1*z2=

Answer 1

$z_1\cdot z_2=(-6+2i)(4-6i)=-24+36i+8i-12\cdot \underbrace {i^2}_{-1}=\\\\=-24+36i+8i+12=-12+44i$

Answer 2

To find the product of two complex numbers, you can use the distributive property and the fact that i^2 is equal to -1. Let's calculate z1 * z2 using the given values:

z1 = -6 + 2i z2 = 4 - 6i

Now, apply the distributive property:

z1 * z2 = (-6 + 2i) * (4 - 6i)

Expand the multiplication:

z1 * z2 = -6 * 4 - 6 * 6i + 2i * 4 - 2i * 6i

Simplify the terms:

z1 * z2 = -24 - 36i + 8i - 12i^2

Since i^2 is equal to -1, substitute it in:

z1 * z2 = -24 - 36i + 8i + 12

Combine the real and imaginary parts:

z1 * z2 = -12 - 28i

So, the product of z1 and z2 is -12 - 28i.