Question

X ------------- = 6 x^2 + 3

Answer 1

Ответ:

x = 6* ( x^2 + 3) = 6x^2 + 18

6 x^2 - x + 18 = 0

D = 1 - 432 = - 431 < 0

Поэтому это уравнение решений не имеет

Answer 2

To solve the equation, let's first write it in a standard quadratic form:

x / (6 x^2 + 3) = 1

Now, to solve for x, we'll clear the fraction by multiplying both sides by (6 x^2 + 3):

x = (6 x^2 + 3)

Next, let's move all the terms to one side of the equation:

6 x^2 + 3 - x = 0

Now, the equation is in the standard quadratic form (ax^2 + bx + c = 0). To solve for x, we can use the quadratic formula:

The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

In our equation, a = 6, b = -1, and c = 3. Substituting these values into the formula:

x = (1 ± √((-1)^2 - 4 * 6 * 3)) / 2 * 6 x = (1 ± √(1 - 72)) / 12 x = (1 ± √(-71)) / 12

Since the discriminant (b^2 - 4ac) is negative, we have complex solutions for x:

x = (1 + √71i) / 12 or x = (1 - √71i) / 12

So the solutions for the equation are complex numbers.