Question

16-а²=x²-4,41=625-a⁴=27+a³=b³-8=​

Answer 1

Ответ:

16 - а² = (4 - a)(4 + a)

x² - 4,41 = (x - 2,1)(x + 2,1)

625 - a⁴ = (25 - а²)(25 + а²)

27 + a³ = (3 + a)(9 - 3a + а²)

b³ - 8 = (b - 2)(b² + 2b + 4)

Answer 2

To solve the given equations, let's tackle them one by one:

1. 16 - a² = x² - 4

To isolate the variable 'a', we can rearrange the equation as follows:

16 - x² + 4 = a²

Simplifying further:

20 - x² = a²

2.41 = 625 - a⁴

Rearranging:

a⁴ = 625 - 2.41

a⁴ = 622.59

To find the value of 'a', we can take the fourth root of both sides:

a = ∛(622.59)

Please note that taking the cube root of a number can result in both positive and negative values. So there will be two possible values for 'a'.

3. 27 + a³ = b³ - 8

Rearranging:

a³ + b³ = 27 + 8

a³ + b³ = 35

Unfortunately, without more information or constraints, we cannot determine the values of 'a' or 'b' uniquely.

Please provide additional information or constraints if you want further assistance with these equations.