Question

X2 - 20 X = -5X - 13 – X2​

Answer 1

Ответ:

2х^2-13х=-13

2х^2-13х+13=0

Д=(-13)^2-4×2×13=169-104=65

Д под корнем равно 65 под корнем

х1/2=13+-65под корнем/4

х1=13+65под корнем/4

х2=13-65под корнем/4

Answer 2

Ответ:

Объяснение:

X² - 20 X = -5X - 13 – X2​

2x²-15x+13=0

Δ=225-101=121

√Δ=11

x1=(15+11)/4=26/4=6,5

x2=(15-11)/4=4/4=1

Answer 3

To solve the given equation, let's first simplify and bring all the terms to one side of the equation. Then we can solve for X.

Given equation: X^2 - 20X = -5X - 13 - X^2

Step 1: Move all terms to one side of the equation: X^2 - 20X + 5X + X^2 = -13

Step 2: Combine like terms: 2X^2 - 15X = -13

Step 3: Bring all terms to one side of the equation: 2X^2 - 15X + 13 = 0

Now, we have a quadratic equation in the standard form (ax^2 + bx + c = 0), where a = 2, b = -15, and c = 13.

To find the solutions for X, we can use the quadratic formula: X = (-b ± √(b^2 - 4ac)) / 2a

Plugging in the values: X = (15 ± √((-15)^2 - 4 * 2 * 13)) / 2 * 2 X = (15 ± √(225 - 104)) / 4 X = (15 ± √121) / 4 X = (15 ± 11) / 4

Now we have two possible solutions for X:

1. X = (15 + 11) / 4 = 26 / 4 = 6.5
2. X = (15 - 11) / 4 = 4 / 4 = 1

So, the solutions for the equation are X = 6.5 and X = 1.