Question

(n^-2/2m^-4)*7n^5m ​

Answer 1

$\displaystyle \tt \frac{n^{-2}}{2m^{-4}}\cdot7n^{5}m=7n^{5}m\cdot\frac{m^{4}}{2n^{2}}=3,5n^{3}m^{5};$

Answer 2

To simplify the expression (n^(-2)/2m^(-4)) * 7n^5m, you can use the rules of exponents. Remember that n^(-x) is equivalent to 1/n^x and m^(-x) is equivalent to 1/m^x.

Step 1: Simplify the fractional part (n^(-2)/2m^(-4)):

n^(-2) = 1/n^2 2m^(-4) = 2/(m^4)

So the fraction becomes (1/n^2) * (1/(2m^4)).

Step 2: Multiply the fractions:

(1/n^2) * (1/(2m^4)) = 1 / (n^2 * 2m^4)

Step 3: Combine the simplified fraction with 7n^5m:

Final expression: 7n^5m * (1 / (n^2 * 2m^4))

Step 4: Simplify further:

To simplify further, you can cancel out one power of 'n' from the numerator and denominator:

Final expression: 7n^(5-2) * (1 / (2m^4))

Final answer: 7n^3 / (2m^4)