Question

(x+5)^2>0 Плииииз!!!

Answer 1

Ответ:

Объяснение:(x+5)²>0⇔x∈(-∞;-5)∪(-5;+∞).

(x+5)²≥0 при всех значениях х∈R,в нашем неравенстве исключаем равенство 0 при х=-5.

Answer 2

Sure, I'd be happy to help!

To solve the inequality $(x+5)^2 > 0$, we need to find the values of $x$ that satisfy the inequality. The square of any real number is always non-negative (greater than or equal to zero). The only way for a square to be strictly greater than zero is if the number being squared is not zero. So, for this inequality to be true, we need $x+5$ to be a non-zero number.

Since $x+5$ is non-zero, it means that $x$ cannot be equal to -5. Any other value for $x$ will satisfy the inequality.

In interval notation, the solution to the inequality is:

$x \in (-\infty, -5) \cup (-5, \infty)$

This means that $x$ can take any value except -5 for the inequality $(x+5)^2 > 0$ to be true.