Question

Y=arccos (cospi)+2arctg 1/2+arcsin(-корень 2/2)-arctg 1

Answer 1

Ответ:

sin(-1/2)= \pi /6

cos( \sqrt{2} /2= \pi /4 или cos( \sqrt{2} /2 = 7 \pi /4

ctg(-1)=cos(-1)/sin(-1)= \pi /( \pi /2= 2

ctg \sqrt{3} =cos \sqrt{3} /sin \sqrt{3}

Объяснение:

изи

Answer 2

Let's simplify the expression step by step:

1. arccos(cos(pi)): The cosine of pi is -1, and arccos(-1) is equal to pi. So, arccos(cos(pi)) = pi.

2. 2 * arctg(1/2): The arctangent (arctg) of 1/2 is approximately 26.565 degrees or π/6 radians. So, 2 * arctg(1/2) = 2 * π/6 = π/3.

3. arcsin(-√2/2): The arcsine (arcsin) of -√2/2 is approximately -45 degrees or -π/4 radians (since arcsin is an odd function). So, arcsin(-√2/2) = -π/4.

4. arctg(1): The arctangent (arctg) of 1 is approximately 45 degrees or π/4 radians. So, arctg(1) = π/4.

Now, let's substitute these values back into the original expression:

Y = π + (π/3) - (π/4) - (π/4)

Now, let's find a common denominator for the fractions:

Y = (4π + 4π - 3π - 3π) / 12 Y = (5π - 3π) / 12 Y = 2π / 12 Y = π / 6

So, the simplified value of Y is π / 6.