Question

(x²-10)-5(x²-10)-6=0​

Answer 1

Представим эту скобку как t

Скобка в квадрате - t^2

t^2-5t-6=0

По теореме Виета:

t1+t2= 5

t1*t2= -6

t1 = 6

t2 = -1

Находим х

1) x^2-10=6

x^2=16

x= +-4

2) x^2-10=-1

x^2=9

x=+-3

Ответ: +-3 ; +-4

Answer 2

To solve the quadratic equation, let's first simplify it:

$x^2 - 10 - 5(x^2 - 10) - 6 = 0$

Distribute the -5:

$x^2 - 10 - 5x^2 + 50 - 6 = 0$

Combine like terms:

$-4x^2 + 34 = 0$

Now, let's isolate the $x^2$ term:

$x^2 = \frac{34}{4}$

$x^2 = 8.5$

Now, take the square root of both sides:

$x = \pm \sqrt{8.5}$

Approximating the square root of 8.5:

$x \approx \pm 2.92$

So the solutions to the quadratic equation are approximately $x \approx 2.92$ and $x \approx -2.92$.