Question

8^(2)−3−5=0 15b^(2)-12=0 2x^(2)-3-x=0 x^(2)-3-x=0

Answer 1

Ответ:

Эм , а какое задание.?

Объяснение:

?

Answer 2

Let's solve each equation step by step:

1. 8^(2)−3−5=0 64 - 3 - 5 = 0 56 - 5 = 0 51 = 0

The equation is not satisfied. There is no solution to this equation.

2. 15b^(2)-12=0 15b^2 = 12 b^2 = 12/15 b^2 = 4/5 b = ±√(4/5)

So the solutions are b = √(4/5) and b = -√(4/5).

3. 2x^(2)-3-x=0 Rearranging the equation: 2x^2 - x - 3 = 0

   We can solve this quadratic equation using the quadratic formula: x = (-b ± √(b^2 - 4ac))/(2a)

   For this equation, a = 2, b = -1, and c = -3.

   x = (1 ± √(1 - 4(2)(-3)))/(2(2)) x = (1 ± √(1 + 24))/4 x = (1 ± √25)/4 x = (1 ± 5)/4

   The two solutions are: x = (1 + 5)/4 = 6/4 = 3/2 x = (1 - 5)/4 = -4/4 = -1

So the solutions to the equation 2x^2 - x - 3 = 0 are x = 3/2 and x = -1.

4. x^(2)-3-x=0 Rearranging the equation: x^2 - x - 3 = 0

   Again, we can solve this quadratic equation using the quadratic formula: x = (-b ± √(b^2 - 4ac))/(2a)

   For this equation, a = 1, b = -1, and c = -3.

   x = (1 ± √(1 - 4(1)(-3)))/(2(1)) x = (1 ± √(1 + 12))/2 x = (1 ± √13)/2

   The two solutions are: x = (1 + √13)/2 x = (1 - √13)/2

So the solutions to the equation x^2 - x - 3 = 0 are x = (1 + √13)/2 and x = (1 - √13)/2.