Question

Sin20°+sin40°-sin100°

Answer 1

$Sin20^{0}+Sin40^{0}-Sin100^{0}=2Sin\frac{20^{0}+40^{0}}{2}Cos\frac{20^{0} -40^{0}}{2}-Sin(90^{0}+10^{0})=2Sin30^{0}Cos10^{0}-Cos10^{0}=2*\frac{1}{2}Cos10^{0}-Cos10^{0}=Cos10^{0}-Cos10^{0}=0$

Answer 2

Ответ:

0

Объяснение:

2sin(30°)cos(-10°)-sin(90°+10°)=2*1/2*cos(10°)-cos(10°)=cos(10°)-cjs(10°)=0

1/2 потрібно записати дрібю.

                                                     

Answer 3

To calculate the value of the expression sin(20°) + sin(40°) - sin(100°), we can use the trigonometric identities and the knowledge that sin(x) is a periodic function with a period of 360°.

Let's break it down step by step:

1. Convert the angles to radians: 20° = (20 * π) / 180 radians 40° = (40 * π) / 180 radians 100° = (100 * π) / 180 radians

2. Apply the trigonometric identities: sin(20°) = sin((20 * π) / 180) sin(40°) = sin((40 * π) / 180) sin(100°) = sin((100 * π) / 180)

3. Evaluate the expressions: sin(20°) ≈ 0.3420 sin(40°) ≈ 0.6428 sin(100°) ≈ -0.9848

4. Substitute the values back into the original expression: sin(20°) + sin(40°) - sin(100°) ≈ 0.3420 + 0.6428 - (-0.9848) ≈ 0.3420 + 0.6428 + 0.9848 ≈ 1.9696

Therefore, sin(20°) + sin(40°) - sin(100°) is approximately equal to 1.9696.