Question

(x - 3y =10(2x - y²=4​

Answer 1

Ответ:

{(4;–2); (34;8)}

Объяснение:

Решение приведено в прикреплённых фотографиях.

Answer 2

It seems like you've written two equations but forgot to close the parentheses for the first equation. I'll assume you meant to write:

1. x - 3y = 10
2. 2x - y² = 4

To solve this system of equations, we can use either the substitution method or the elimination method. Let's use the substitution method:

Step 1: Solve one equation for one variable in terms of the other variable. Let's solve the first equation (1) for x: x = 10 + 3y

Step 2: Substitute the expression for x from Step 1 into the second equation (2): 2(10 + 3y) - y² = 4

Step 3: Simplify and solve for y: 20 + 6y - y² = 4 Rearrange to get the equation in standard form: y² - 6y + 20 = 0

Step 4: Solve the quadratic equation for y. You can use the quadratic formula: y = (6 ± √(6² - 4120)) / 2 y = (6 ± √(36 - 80)) / 2 y = (6 ± √(-44)) / 2

Since the discriminant (√(-44)) is negative, this equation has no real solutions for y. Hence, there are no real solutions for x either.

In conclusion, the system of equations you provided does not have real solutions. The two equations represent two curves that do not intersect in the real plane.